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11x^2+33x-44=0
a = 11; b = 33; c = -44;
Δ = b2-4ac
Δ = 332-4·11·(-44)
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3025}=55$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-55}{2*11}=\frac{-88}{22} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+55}{2*11}=\frac{22}{22} =1 $
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